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QUANT Advance level question With solution SSC + BANK and other exams @BANKING_QUANT👈 join this group ( Mathsfundamentals) For Discussion
Meeting time=560/120=>4⅔hrs
D=4⅔*30=>140km
2/3=24
01=36days
=>36. C=1. BC=4. B=3
B=36/3=>12days
AB : A
3. : 1
A : B
1 : 2. 2=3. 1=3/2
A alone work=36*2/3=>24days
2πr(r+h): 3πr²
2(2+1):3*1
2. : 1. =>1/1=>100%
4 : 8
80=4
100=5. 8-5=3
%=3/12=>1/4=>25%
a=200+b
7b+4.5b=4600
11.5b=4600. B=400 a=600
5A+4.5B=12B
5A=7.5B
A/B=3/2
Total=12*2=24
N=24/3=8
a - b = 3)*115
115b + 90a = 2115
205a == 2460
100a ==> 1200
1/4 = 5/12(1- 240/x)
X = 50 24x = 1200
42 0
35
35 : 7= 5 : 1
6 = 1200
Kerosene = 1 = 200 liters
35%= 126
100%= 360
360 : 540 = 2 : 3 , q = 50%
360 × 1.3= 468₹
21a = 15b , a : b = 5 : 7
Tym = 48×5)/12= 20 days
Int=4800/4 =1200
1200=p*R/100
Pr=120000
P=120000/r
A=p(1+r/100)^2 .....1
Put value of p in 1..
14520 =12(100+r)^2/r
R^2-1010r+10000=0
R=10%✔
S) 4 5
T) 5 4
1 == 36
5 == 180
12*3 == 36km
36*5/48 == 3hr 45min
4000/10600=40/106=>>20/53
20 : 33
11=33 1=3. 6=18 5=15
18 : 15 : 20
2=600. 1=300 18=3600
12½%=1/8
6⅔%=1/15
AJ : SU : SA
9. :. 8)5
16. 15)3
48. 45. 40
8=40. 133=665
A - b = 200)*7
7a+4.5b = 6000
---------------
11.5b = 4600
B = 400
A = (400+200)= 600
How to solve these two equations ?
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1 : 3
8=2
1=1/4
1 : 7
Int=6. Tym=6/1/4=>24yrs
Short:-
2time=8yrs
6time=24yrs
C=100%+300)90%=90%+270
T=100*115%=>115%
205%=1845
100%=900. 100%+300=>1200
5×12 : 10 ×10 : 6×20 = 3 : 5 : 6
14 = 350000
5 = 125,000₹
d1 = 432/18+ 4 = 28
d2 = 80/4 × 80%= 16
Area = 1/2 × 28 × 16 = 224 cm²
x- y = 6*60/18 = 20
x+y = 12*60/12 = 60
x = 40
y = 20
Y ko double kr rha = 40
Time bhi double bol rha
x-y = 6*60/36 = 10
x = 50
10/40 = 25% increase
G B
X (X+14)
35
9 : 5
X = 30
Boys(avg) = 44
No of boys = 25
25*44 == 1100
50/(20*5/18)= 9 sec
4 mins 9 sec = 249 secs by Group B
125/(25*5/18)= 18 sec
4 mins - 18 sec = 222 secs after increase
249 : 222 time
222 : 249 speed
27/222= 12.16% ~ 12.15% ans solved by someone
600=b*2b*2/b
B=150 kmph
Tym by b=600/150 =4 hr
Tym by a=6 hr
Speed of A=600/6 =100kmph ✔